MGT601 - SME Management
Question(s) similar to the following:
Two resistors R1 and R2 of 5 each and R3 of 10 are in series. How much is RT. If we applied 80 V source across the series string, how much is the current in R3.
Question 1: Two resistors R1 and R2 of 5 each and R3 of 10 are in series. How much is RT. If we applied 80 V source across the series string, how much is the current in R3.
Answer: Suggest Edit
RT = R1+R2+R3 = 5+5+10 = 20
I = VT/RT = 80/ 20 = 4A
Similar Questions:
Question 2: Two resistors R1 and R2 of 5 each and R3 of 10 are in series. How much is RT. If we applied 80 V source across the series string, how much is the current in R3.
Answer: Suggest Edit
RT = R1+R2+R3 = 5+5+10 = 20
I = VT/RT = 80/ 20 = 4A
Past Papers of MGT601 - SME Management
Question 1: Two resistors R1 and R2 of 5 each and R3 of 10 are in series. How much is RT. If we applied 80 V source across the series string, how much is the current in R3.
Answer: Suggest Edit
RT = R1+R2+R3 = 5+5+10 = 20I = VT/RT = 80/ 20 = 4A
Similar Questions:
Question 2: Two resistors R1 and R2 of 5 each and R3 of 10 are in series. How much is RT. If we applied 80 V source across the series string, how much is the current in R3.
Answer: Suggest Edit
RT = R1+R2+R3 = 5+5+10 = 20I = VT/RT = 80/ 20 = 4A
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